From 663236797854b1802909ed0ed1d66bc8ed71baa6 Mon Sep 17 00:00:00 2001
From: Paul Gauthier <aider@paulg.org>
Date: Wed, 28 Jun 2023 18:29:58 -0700
Subject: [PATCH] aider: Refactor `run_unit_tests` to kill the subprocess when
 it times out.

# Context:
USER: when `subprocess` `timeout` fires, do we need to kill the subprocess? just in `run_unit_tests`
ASSISTANT: When a subprocess times out, it is not automatically terminated. So, yes, if you want to ensure that the subprocess is terminated when it times out, you should explicitly kill it.

Here's how you can modify the `run_unit_tests` function to kill the subprocess when it times out:

```python
benchmark/benchmark.py
<<<<<<< ORIGINAL
        try:
            result = subprocess.run(
                command,
                stdout=subprocess.PIPE,
                stderr=subprocess.STDOUT,
                text=True,
                timeout=timeout,
            )
            if result.returncode != 0:
                all_tests_passed = False
                print(f"Test {test_file} failed")

            res = cleanup_test_output(result.stdout)

        except subprocess.TimeoutExpired:
            all_tests_passed = False
            res = f"Test {test_file} timed out after {timeout} seconds."
=======
        with subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.STDOUT, text=True) as proc:
            try:
                stdout, _ = proc.communicate(timeout=timeout)
                if proc.returncode != 0:
                    all_tests_passed = False
                    print(f"Test {test_file} failed")
                res = cleanup_test_output(stdout)
            except subprocess.TimeoutExpired:
                proc.kill()
                proc.wait()
                all_tests_passed = False
                res = f"Test {test_file} timed out after {timeout} seconds."
>>>>>>> UPDATED
```

This change uses `subprocess.Popen` to create the subprocess and `communicate` to interact with it. If `communicate` times out, it raises `subprocess.TimeoutExpired`, and then we kill the subprocess with `proc.kill()`.
---
 benchmark/benchmark.py | 27 +++++++++++----------------
 1 file changed, 11 insertions(+), 16 deletions(-)

diff --git a/benchmark/benchmark.py b/benchmark/benchmark.py
index 746ff4a49..9a1f54c26 100755
--- a/benchmark/benchmark.py
+++ b/benchmark/benchmark.py
@@ -374,23 +374,18 @@ def run_unit_tests(testdir, history_fname):
         ]
         print(" ".join(command))
 
-        try:
-            result = subprocess.run(
-                command,
-                stdout=subprocess.PIPE,
-                stderr=subprocess.STDOUT,
-                text=True,
-                timeout=timeout,
-            )
-            if result.returncode != 0:
+        with subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.STDOUT, text=True) as proc:
+            try:
+                stdout, _ = proc.communicate(timeout=timeout)
+                if proc.returncode != 0:
+                    all_tests_passed = False
+                    print(f"Test {test_file} failed")
+                res = cleanup_test_output(stdout)
+            except subprocess.TimeoutExpired:
+                proc.kill()
+                proc.wait()
                 all_tests_passed = False
-                print(f"Test {test_file} failed")
-
-            res = cleanup_test_output(result.stdout)
-
-        except subprocess.TimeoutExpired:
-            all_tests_passed = False
-            res = f"Test {test_file} timed out after {timeout} seconds."
+                res = f"Test {test_file} timed out after {timeout} seconds."
 
         with history_fname.open("a") as fh:
             fh.write(f"```\n{res}\n```")